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Ch. 2 - Limits
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 11

Assume lim x→1 f(x)=8,lim x→1 g(x)=3, and lim x→1 h(x)=2 Compute the following limits and state the limit laws used to justify your computations.


lim x→1 f(x) / g(x)−h(x)

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1
Identify the given limits: \( \lim_{{x \to 1}} f(x) = 8 \), \( \lim_{{x \to 1}} g(x) = 3 \), and \( \lim_{{x \to 1}} h(x) = 2 \).
Recognize that the problem requires finding \( \lim_{{x \to 1}} \frac{f(x)}{g(x) - h(x)} \).
Apply the limit law for quotients: \( \lim_{{x \to a}} \frac{f(x)}{g(x)} = \frac{\lim_{{x \to a}} f(x)}{\lim_{{x \to a}} g(x)} \) provided \( \lim_{{x \to a}} g(x) \neq 0 \).
Calculate the limit of the denominator: \( \lim_{{x \to 1}} (g(x) - h(x)) = \lim_{{x \to 1}} g(x) - \lim_{{x \to 1}} h(x) = 3 - 2 = 1 \).
Use the quotient limit law: \( \lim_{{x \to 1}} \frac{f(x)}{g(x) - h(x)} = \frac{\lim_{{x \to 1}} f(x)}{\lim_{{x \to 1}} (g(x) - h(x))} = \frac{8}{1} \).

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