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Ch. 2 - Limits
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBriggs 3rd EditionCh. 2 - LimitsProblema 13
Capitolo 2, Problema 13

Determine the following limits.
lim h→0 (h + 6)^2 + (h + 6) − 42 / h

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Step 1: Identify the expression whose limit we need to find. The expression is \( \frac{(h + 6)^2 + (h + 6) - 42}{h} \).
Step 2: Simplify the numerator. Expand \((h + 6)^2\) to get \(h^2 + 12h + 36\).
Step 3: Combine the terms in the numerator. The expression becomes \(h^2 + 12h + 36 + h + 6 - 42\).
Step 4: Simplify the combined terms. This results in \(h^2 + 13h\).
Step 5: Factor the numerator. The expression \(h^2 + 13h\) can be factored as \(h(h + 13)\).

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Limits

Limits are fundamental in calculus, representing the value that a function approaches as the input approaches a certain point. They are essential for understanding continuity, derivatives, and integrals. In this question, evaluating the limit as h approaches 0 helps determine the behavior of the function near that point.
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One-Sided Limits

Algebraic Manipulation

Algebraic manipulation involves rearranging and simplifying expressions to make calculations easier. In the context of limits, it often includes factoring, expanding, or combining like terms to eliminate indeterminate forms such as 0/0. This skill is crucial for simplifying the expression before applying limit laws.
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L'Hôpital's Rule

L'Hôpital's Rule is a method used to evaluate limits that result in indeterminate forms like 0/0 or ∞/∞. It states that if such a form occurs, the limit of the ratio of two functions can be found by taking the derivative of the numerator and the derivative of the denominator. This rule can simplify the process of finding limits in complex expressions.
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