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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.9.42

15–48. Derivatives Find the derivative of the following functions.
y = 10^In 2x

Guida verificata passo dopo passo
1
Step 1: Recognize that the function y = 10^ln(2x) can be rewritten using the property of logarithms and exponents. Recall that ln(a^b) = b * ln(a), so we can express the function as y = e^(ln(10) * ln(2x)).
Step 2: Apply the chain rule to differentiate the function. The chain rule states that if you have a composite function y = f(g(x)), then the derivative y' = f'(g(x)) * g'(x). Here, let u = ln(10) * ln(2x), so y = e^u.
Step 3: Differentiate y = e^u with respect to u. The derivative of e^u with respect to u is e^u. Therefore, dy/du = e^u.
Step 4: Differentiate u = ln(10) * ln(2x) with respect to x. Use the product rule and the chain rule. The product rule states that if u = v * w, then du/dx = v' * w + v * w'. Here, v = ln(10) and w = ln(2x).
Step 5: Differentiate w = ln(2x) with respect to x. Use the chain rule: the derivative of ln(2x) is (1/(2x)) * (d/dx)(2x) = 1/x. Combine this with the previous steps to find the derivative of the original function.

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Derivatives

A derivative represents the rate at which a function changes at any given point. It is a fundamental concept in calculus that measures how a function's output value changes as its input value changes. The derivative can be interpreted as the slope of the tangent line to the curve of the function at a specific point.
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Chain Rule

The chain rule is a fundamental technique in calculus used to differentiate composite functions. It states that if a function y = f(g(x)) is composed of two functions, the derivative can be found by multiplying the derivative of the outer function f with the derivative of the inner function g. This rule is essential for handling functions where one function is nested within another.
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