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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
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Tutti i libri di testoBriggs 3rd EditionCh. 3 - DerivativesProblema 3.28
Capitolo 3, Problema 3.28

Derivatives Find the derivative of the following functions. See Example 2 of Section 3.2 for the derivative of √x.
g(t) = 6√t

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Step 1: Recognize that the function g(t) = 6√t can be rewritten using exponent notation as g(t) = 6t^{1/2}.
Step 2: Apply the power rule for differentiation, which states that if f(t) = t^n, then f'(t) = n*t^{n-1}.
Step 3: Differentiate g(t) = 6t^{1/2} using the power rule. The derivative of t^{1/2} is (1/2)t^{-1/2}.
Step 4: Multiply the derivative of t^{1/2} by the constant 6, resulting in g'(t) = 6 * (1/2)t^{-1/2}.
Step 5: Simplify the expression to find the derivative g'(t) = 3t^{-1/2}.

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Derivatives

A derivative represents the rate of change of a function with respect to its variable. It is a fundamental concept in calculus that provides information about the slope of the tangent line to the curve of the function at any given point. The derivative can be computed using various rules, such as the power rule, product rule, and chain rule.
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Derivatives

Power Rule

The power rule is a basic technique for finding the derivative of functions of the form f(x) = x^n, where n is a real number. According to this rule, the derivative f'(x) is given by n*x^(n-1). This rule simplifies the differentiation process, especially for polynomial functions and can be applied to functions involving roots, such as √t.
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Power Rules

Square Root Function

The square root function, denoted as √x, is a specific type of function that returns the non-negative square root of x. In calculus, it is important to understand how to differentiate this function, as it can be expressed in terms of exponents (x^(1/2)). This transformation allows the application of the power rule to find its derivative effectively.
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Multiplying & Dividing Functions
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