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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.91c

Derivatives from a graph If possible, evaluate the following derivatives using the graphs of f and f'. <IMAGE>
c. (f^-1)'(f(2))

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To solve this problem, we need to use the formula for the derivative of the inverse function. The formula is: (f^{-1})'(x) = 1 / f'(f^{-1}(x)).
First, identify f(2) from the graph of f. This value is the input for the inverse function f^{-1}.
Next, find the value of f^{-1}(f(2)) using the graph of f. This is the x-value for which f(x) equals f(2).
Once you have f^{-1}(f(2)), use the graph of f' to find f'(f^{-1}(f(2))). This is the derivative of f at the point f^{-1}(f(2)).
Finally, apply the formula: (f^{-1})'(f(2)) = 1 / f'(f^{-1}(f(2))). This will give you the derivative of the inverse function at the point f(2).

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Inverse Function Theorem

The Inverse Function Theorem states that if a function f is continuous and differentiable, and its derivative f' is non-zero at a point, then the inverse function f^-1 exists locally around that point. This theorem is crucial for understanding how to differentiate inverse functions and relates the derivatives of f and f^-1.
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Chain Rule

The Chain Rule is a fundamental principle in calculus that allows us to differentiate composite functions. It states that if you have a function g(f(x)), the derivative is g'(f(x)) * f'(x). This rule is essential when dealing with derivatives of inverse functions, as it helps in relating the derivatives of f and its inverse.
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Intro to the Chain Rule

Evaluating Derivatives at Specific Points

To evaluate derivatives at specific points, one must first find the value of the function at that point and then apply the appropriate derivative rules. In the context of the question, evaluating (f^-1)'(f(2)) requires finding f(2) and then using the Inverse Function Theorem to determine the derivative of the inverse function at that point.
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Critical Points
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c. Explain why it is not necessary to use negative values of h in the table of part (b).

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