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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.R.67

Higher-order derivatives Find and simplify y''.
y = 2^x x

Guida verificata passo dopo passo
1
First, identify the function y = 2^x * x. This is a product of two functions, so we will use the product rule to find the first derivative y'.
Apply the product rule: If y = u * v, then y' = u' * v + u * v'. Here, let u = 2^x and v = x. Find the derivatives u' and v'.
Calculate u': The derivative of 2^x with respect to x is 2^x * ln(2).
Calculate v': The derivative of x with respect to x is 1.
Substitute u', v, u, and v' into the product rule formula to find y'. Then, differentiate y' again to find y'', applying the product rule and chain rule as necessary. Simplify the expression for y''.

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The product rule is a fundamental differentiation technique used when finding the derivative of a product of two functions. If u(x) and v(x) are two differentiable functions, the product rule states that the derivative of their product is given by u'v + uv'. This rule is crucial for differentiating functions like y = 2^x * x, where both components depend on x.
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