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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.9.7

Simplify the expression e^xln(x²+1).

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First, recognize that the expression involves the natural logarithm function ln and the exponential function e. The expression is e raised to the power of x times ln(x² + 1).
Use the property of logarithms that states ln(a^b) = b * ln(a). In this case, you can rewrite ln(x² + 1) as ln((x² + 1)^1), which is simply ln(x² + 1).
Next, apply the property of exponents that states e^(a * ln(b)) = b^a. This allows you to simplify e^(x * ln(x² + 1)) to (x² + 1)^x.
Now, the expression is simplified to (x² + 1)^x. This is the simplified form of the original expression.
Finally, verify the simplification by considering the properties used: the logarithmic identity and the exponential identity. Ensure that each step logically follows from the previous one.

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Exponential Functions

Exponential functions are mathematical expressions in the form of a constant raised to a variable exponent, commonly represented as e^x, where e is Euler's number (approximately 2.718). These functions exhibit unique properties, such as the derivative of e^x being e^x itself, which is crucial for simplification and differentiation in calculus.
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