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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.5.17

Use Theorem 3.10 to evaluate the following limits.
lim x🠂0 (tan 7x) / (sin x)

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Theorem 3.10 refers to the limit of a function as it approaches a point, often involving L'Hôpital's Rule when dealing with indeterminate forms like 0/0. First, check if the limit results in an indeterminate form by substituting x = 0 into the expression (tan 7x) / (sin x).
Substitute x = 0 into tan(7x) and sin(x). Both tan(7x) and sin(x) approach 0 as x approaches 0, resulting in the indeterminate form 0/0. This indicates that L'Hôpital's Rule can be applied.
Apply L'Hôpital's Rule, which states that if the limit of f(x)/g(x) as x approaches a value results in 0/0 or ∞/∞, then the limit can be found by differentiating the numerator and the denominator separately. Differentiate the numerator tan(7x) and the denominator sin(x) with respect to x.
The derivative of tan(7x) with respect to x is 7sec²(7x), and the derivative of sin(x) with respect to x is cos(x). Substitute these derivatives back into the limit expression, resulting in lim x→0 (7sec²(7x)) / (cos(x)).
Evaluate the new limit expression as x approaches 0. Substitute x = 0 into the expression 7sec²(7x) / cos(x). Since sec(7x) = 1/cos(7x), and cos(0) = 1, the expression simplifies to 7 * (1/1)² / 1, which can be further simplified to find the limit.

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