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Ch. 4 - Applications of the Derivative
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.7.28

17–83. Limits Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.


lim_x→ 0⁺ (x - 3 √x) / (x - √x)

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Identify the form of the limit as x approaches 0 from the positive side. Substitute x = 0 into the expression (x - 3√x) / (x - √x) to check if it results in an indeterminate form like 0/0.
Since substituting x = 0 gives 0/0, l'Hôpital's Rule can be applied. This rule states that if the limit of f(x)/g(x) as x approaches a point results in an indeterminate form, then the limit can be found by differentiating the numerator and the denominator separately.
Differentiate the numerator: The numerator is x - 3√x. The derivative of x is 1, and the derivative of 3√x is (3/2)x^(-1/2). Therefore, the derivative of the numerator is 1 - (3/2)x^(-1/2).
Differentiate the denominator: The denominator is x - √x. The derivative of x is 1, and the derivative of √x is (1/2)x^(-1/2). Therefore, the derivative of the denominator is 1 - (1/2)x^(-1/2).
Apply l'Hôpital's Rule: Take the limit of the new expression formed by the derivatives of the numerator and the denominator as x approaches 0 from the positive side. Evaluate lim_x→0⁺ [(1 - (3/2)x^(-1/2)) / (1 - (1/2)x^(-1/2))].

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