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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 5.2.53.d

Properties of integrals Suppose ∫₀³ƒ(𝓍) d𝓍 = 2 , ∫₃⁶ƒ(𝓍) d𝓍 = ―5 , and ∫₃⁶g(𝓍) d𝓍 = 1. Evaluate the following integrals.
(d) ∫₆³ (ƒ(𝓍) + 2g(𝓍)) d𝓍

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Step 1: Recognize that the integral ∫₆³ (ƒ(𝓍) + 2g(𝓍)) d𝓍 involves reversing the limits of integration. When the limits are reversed, the integral changes sign. Thus, ∫₆³ (ƒ(𝓍) + 2g(𝓍)) d𝓍 = -∫₃⁶ (ƒ(𝓍) + 2g(𝓍)) d𝓍.
Step 2: Use the property of linearity of integrals to split the integral into two separate integrals: -∫₃⁶ (ƒ(𝓍) + 2g(𝓍)) d𝓍 = -[∫₃⁶ ƒ(𝓍) d𝓍 + ∫₃⁶ 2g(𝓍) d𝓍].
Step 3: Factor out the constant 2 from the second integral using the constant multiple rule: -[∫₃⁶ ƒ(𝓍) d𝓍 + 2∫₃⁶ g(𝓍) d𝓍].
Step 4: Substitute the given values for the integrals: ∫₃⁶ ƒ(𝓍) d𝓍 = -5 and ∫₃⁶ g(𝓍) d𝓍 = 1. Replace these values into the expression: -[-5 + 2(1)].
Step 5: Simplify the expression inside the brackets and apply the negative sign outside the brackets to find the result.

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Properties of Definite Integrals

Definite integrals have several key properties, including linearity, which states that the integral of a sum is the sum of the integrals. This means that ∫(f(x) + g(x)) dx = ∫f(x) dx + ∫g(x) dx. Additionally, the integral from a to b can be expressed as the negative of the integral from b to a, i.e., ∫_a^b f(x) dx = -∫_b^a f(x) dx.
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Definition of the Definite Integral

Change of Limits in Integrals

When evaluating integrals, changing the limits of integration affects the sign of the result. Specifically, if you reverse the limits of integration, the value of the integral becomes negative. For example, ∫_a^b f(x) dx = -∫_b^a f(x) dx, which is crucial when evaluating integrals with limits that are not in increasing order.
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Changing Geometries

Linear Combination of Functions

A linear combination of functions involves adding or subtracting functions multiplied by constants. In the context of integrals, if you have a function like (f(x) + 2g(x)), you can evaluate the integral of this combination by integrating each function separately and applying the constants accordingly. This property simplifies the evaluation of integrals involving multiple functions.
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