Skip to main content
Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBriggs 3rd EditionCh. 5 - IntegrationProblema 5.2.24b
Capitolo 5, Problema 5.2.24b

{Use of Tech} Approximating net area The following functions are positive and negative on the given interval.
f(𝓍) = x³ on [-1,2]
(b) Approximate the net area bounded by the graph of f and the x-axis on the interval using a left, right, and midpoint Riemann sum with n = 4.

Guida verificata passo dopo passo
1
Step 1: Understand the problem. You are tasked with approximating the net area bounded by the graph of f(x) = x³ and the x-axis on the interval [-1, 2] using Riemann sums (left, right, and midpoint) with n = 4 subintervals.
Step 2: Divide the interval [-1, 2] into n = 4 equal subintervals. The width of each subinterval, Δx, is calculated as Δx = (b - a) / n, where a = -1 and b = 2. Substitute the values to find Δx.
Step 3: Determine the x-values for the subintervals. For n = 4, the subintervals are [-1, -0.25], [-0.25, 0.5], [0.5, 1.25], and [1.25, 2]. Identify the left endpoints, right endpoints, and midpoints of each subinterval.
Step 4: Compute the Riemann sums. For each type of sum: (a) Left Riemann sum: Evaluate f(x) at the left endpoints of each subinterval and multiply by Δx. (b) Right Riemann sum: Evaluate f(x) at the right endpoints of each subinterval and multiply by Δx. (c) Midpoint Riemann sum: Evaluate f(x) at the midpoints of each subinterval and multiply by Δx.
Step 5: Add the contributions from each subinterval for the left, right, and midpoint Riemann sums. This will give you the approximate net area for each method. Note that the net area accounts for both positive and negative contributions of f(x) over the interval.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
4m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Riemann Sums

Riemann sums are a method for approximating the total area under a curve by dividing the region into smaller subintervals. Each subinterval's area is estimated using the function's value at specific points, such as the left endpoint, right endpoint, or midpoint. The sum of these areas provides an approximation of the net area between the curve and the x-axis over the specified interval.
Video consigliato:
Percorso guidato
06:11
Introduction to Riemann Sums

Net Area

The net area refers to the total area between a curve and the x-axis, accounting for both positive and negative areas. When a function is above the x-axis, the area is considered positive, while areas below the x-axis are negative. The net area is calculated by subtracting the negative area from the positive area, providing a comprehensive measure of the total area over the given interval.
Video consigliato:
05:06
Finding Area When Bounds Are Not Given

Interval Division

Interval division involves breaking down a continuous interval into smaller segments to facilitate calculations, such as Riemann sums. In this case, the interval [-1, 2] is divided into four equal parts, allowing for the evaluation of the function at specific points within each subinterval. This division is crucial for accurately approximating the area under the curve using the chosen Riemann sum method.
Video consigliato:
08:44
Interval of Convergence
Pratica correlata
Domanda del libro di testo

Area functions for the same linear function Let ƒ(t) = t and consider the two area functions A(𝓍) = ∫₀ˣ ƒ(t) dt and F(𝓍) = ∫₂ˣ ƒ(t) dt .

(b) Evaluate F(4) and F(6). Then use geometry to find an expression for F (𝓍) , for 𝓍 ≥ 2. 

42
views
Domanda del libro di testo

Sigma notation Evaluate the following expressions.                                                                                                                                          

(b)    10                                                                                                                                                                               

       ∑  (2κ + 1)                                                                                                                                                                          

       κ=1                         

83
views
Domanda del libro di testo

Displacement from a velocity graph Consider the velocity function for an object moving along a line (see figure).

(b) Use geometry to find the displacement of the object between t = 0 and t = 2.

123
views
Domanda del libro di testo

Mass from density A thin 10-cm rod is made of an alloy whose density varies along its length according to the function shown in the figure. Assume density is measured in units of g/cm. In Chapter 6, we show that the mass of the rod is the area under the density curve.

(a) Find the mass of the left half of the rod (0 ≤ x ≤ 5) .

63
views
Domanda del libro di testo

Properties of integrals Use only the fact that ∫₀⁴ 3𝓍 (4 ―𝓍) d𝓍 = 32, and the definitions and properties of integrals, to evaluate the following integrals, if possible.

(b) ∫₀⁴ 𝓍(𝓍 ― 4) d(𝓍)

65
views
Domanda del libro di testo

Mass from density A thin 10-cm rod is made of an alloy whose density varies along its length according to the function shown in the figure. Assume density is measured in units of g/cm. In Chapter 6, we show that the mass of the rod is the area under the density curve.

(b) Find the mass of the right half of the rod (5 ≤ x ≤ 10) .

46
views