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Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.3.47

37–56. Integrals Evaluate each integral.
∫ dx/(8 – x²), x > 2√2

Guida verificata passo dopo passo
1
Recognize that the integral is of the form \(\int \frac{dx}{a^2 - x^2}\), where \(a^2 = 8\), so \(a = 2\sqrt{2}\).
Recall the standard integral formula: \(\int \frac{dx}{a^2 - x^2} = \frac{1}{2a} \ln \left| \frac{a + x}{a - x} \right| + C\), valid for \(|x| > a\).
Since the problem states \(x > 2\sqrt{2}\), the condition for the formula applies directly.
Substitute \(a = 2\sqrt{2}\) into the formula to write the integral in terms of \(x\) and \(a\).
Write the final expression for the integral as \(\frac{1}{2 \cdot 2\sqrt{2}} \ln \left| \frac{2\sqrt{2} + x}{2\sqrt{2} - x} \right| + C\), simplifying the coefficient if desired.

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Domain Restrictions and Absolute Values

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