Skip to main content
Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.3.79a

Evaluating hyperbolic functions Evaluate each expression without using a calculator or state that the value does not exist. Simplify answers as much as possible.


a. cosh 0

Guida verificata passo dopo passo
1
Recall the definition of the hyperbolic cosine function: \(\cosh x = \frac{e^{x} + e^{-x}}{2}\).
Substitute \(x = 0\) into the definition: \(\cosh 0 = \frac{e^{0} + e^{-0}}{2}\).
Evaluate the exponentials: \(e^{0} = 1\) and \(e^{-0} = 1\).
Add the values in the numerator: \(1 + 1 = 2\).
Divide by 2 to simplify: \(\cosh 0 = \frac{2}{2}\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Definition of Hyperbolic Cosine (cosh)

The hyperbolic cosine function, cosh(x), is defined as (e^x + e^(-x)) / 2. It is an even function and describes the shape of a hanging cable or chain (catenary). Understanding this definition allows direct evaluation of cosh at any point, including zero.
Video consigliato:
Percorso guidato
05:43
Definition of the Definite Integral

Properties of Exponential Functions

Exponential functions e^x and e^(-x) are fundamental in defining hyperbolic functions. Knowing that e^0 = 1 simplifies calculations, especially when evaluating cosh(0), since it involves e^0 and e^(-0). This property helps in simplifying expressions without a calculator.
Video consigliato:
Percorso guidato
06:21
Properties of Functions

Evaluating Functions at Specific Points

Evaluating a function at a specific point means substituting the value into the function's formula and simplifying. For cosh(0), substituting x=0 into the definition and simplifying using known values of exponentials yields the exact result without approximation.
Video consigliato:
Percorso guidato
4:26
Evaluating Composed Functions
Pratica correlata
Domanda del libro di testo

Visual approximation


a. Use a graphing utility to sketch the graph of y = coth x and then explain why ∫₅¹⁰ coth x dx ≈ 5.

42
views
Domanda del libro di testo

Chemotherapy In an experimental study at Dartmouth College, mice with tumors were treated with the chemotherapeutic drug Cisplatin. Before treatment, the tumors consisted entirely of clonogenic cells that divide rapidly, causing the tumors to double in size every 2.9 days. Immediately after treatment, 99% of the cells in the tumor became quiescent cells which do not divide and lose 50% of their volume every 5.7 days. For a particular mouse, assume the tumor size is 0.5 cm³ at the time of treatment.

a. Find an exponential decay function V₁(t) that equals the total volume of the quiescent cells in the tumor t days after treatment.

47
views
Domanda del libro di testo

Zero net area Consider the function f(x) = (1 − x)/x

a. Are there numbers 0 < a < 1 such that ∫₁₋ₐ¹⁺ᵃ f(x) dx = 0?

34
views
Domanda del libro di testo

Energy consumption On the first day of the year (t=0), a city uses electricity at a rate of 2000 MW. That rate is projected to increase at a rate of 1.3% per year.


a. Based on these figures, find an exponential growth function for the power (rate of electricity use) for the city.

45
views
Domanda del libro di testo

Terminal velocity Refer to Exercises 95 and 96.


a. Compute a jumper’s terminal velocity, which is defined as lim t → ∞ v(t) = lim t → ∞ √(mg/k) tanh (√(kg/m) t).

65
views
Domanda del libro di testo

Falling body When an object falling from rest encounters air resistance proportional to the square of its velocity, the distance it falls (in meters) after t seconds is given by d(t) = (m/k) ln (cosh (√(kg/m) t)), where m is the mass of the object in kilograms, g = 9.8 m/s² is the acceleration due to gravity, and k is a physical constant.


a. A BASE jumper (m = 75 kg) leaps from a tall cliff and performs a ten-second delay (she free-falls for 10 s and then opens her chute). How far does she fall in 10 s? Assume k = 0.2.

54
views