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Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.1.67

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. Assume x > 0 and y > 0.


d. 2ˣ = 2² ˡⁿ ˣ

Guida verificata passo dopo passo
1
Recall the properties of exponents and logarithms. The expression 2^{x} means 2 raised to the power x.
The expression 2^{2 \(\ln\) x} can be rewritten using the property a^{b} = e^{b \(\ln\) a}, so 2^{2 \(\ln\) x} = e^{(2 \(\ln\) x)(\(\ln\) 2)}.
Compare 2^{x} and 2^{2 \(\ln\) x} by expressing both in terms of the exponential function with base e: 2^{x} = e^{x \(\ln\) 2} and 2^{2 \(\ln\) x} = e^{2 \(\ln\) x \(\cdot\) \(\ln\) 2}.
Since x > 0 and y > 0, analyze whether the exponents x \(\ln\) 2 and 2 \(\ln\) x \(\cdot\) \(\ln\) 2 are equal for all x > 0. This requires checking if x = 2 \(\ln\) x holds for all x > 0.
Test the equality by substituting specific positive values of x to see if 2^{x} equals 2^{2 \(\ln\) x}. If they are not equal for all x, then the statement is false and the substitution serves as a counterexample.

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