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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.9.4

4. Evaluate ∫ (from 0 to 1) (1/x^(1/5)) dx after writing the integral as a limit.

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Rewrite the integral \( \int_0^1 \frac{1}{x^{1/5}} \, dx \) as \( \int_0^1 x^{-1/5} \, dx \) to express the integrand with a negative exponent, which is easier to integrate.
Recognize that the integrand \( x^{-1/5} \) is undefined at \( x = 0 \) because it involves division by zero, so the integral is an improper integral and must be expressed as a limit.
Express the integral as a limit approaching 0 from the right: \[ \lim_{t \to 0^+} \int_t^1 x^{-1/5} \, dx \]. This handles the improper behavior at the lower limit.
Find the antiderivative of \( x^{-1/5} \) using the power rule for integration: \[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \] where \( n = -\frac{1}{5} \). So, \[ \int x^{-1/5} \, dx = \frac{x^{4/5}}{4/5} + C = \frac{5}{4} x^{4/5} + C \].
Evaluate the definite integral by substituting the limits into the antiderivative and then take the limit as \( t \to 0^+ \): \[ \lim_{t \to 0^+} \left( \frac{5}{4} (1)^{4/5} - \frac{5}{4} t^{4/5} \right) \].

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Power Rule for Integration

The power rule states that ∫ x^n dx = (x^(n+1)) / (n+1) + C for n ≠ -1. This rule helps integrate functions with variable exponents, such as x^(-1/5), by increasing the exponent by one and dividing by the new exponent.
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