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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBriggs 3rd EditionCh. 8 - Integration TechniquesProblema 8.9.44
Capitolo 8, Problema 8.9.44

7–58. Improper integrals Evaluate the following integrals or state that they diverge.
44. ∫ (from 0 to ln 3) eʸ/(eʸ-1)⁷ᐟ³ dy

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1
Identify the integral to evaluate: \(\int_0^{\ln 3} \frac{e^y}{(e^y - 1)^{7/3}} \, dy\).
Check the behavior of the integrand at the limits of integration, especially near \(y=0\) and \(y=\ln 3\), to determine if the integral is improper. Note that at \(y=0\), \(e^y - 1 = 0\), which may cause a singularity.
To analyze the singularity at \(y=0\), perform a substitution or use a limit approach. For example, let \(x = e^y - 1\), so when \(y \to 0\), \(x \to 0\). Express the integrand in terms of \(x\) and examine the limit as \(x \to 0\).
Rewrite the integral using the substitution \(x = e^y - 1\), which implies $dx = e^y dy = (x + 1) dy$, so \(dy = \frac{dx}{x + 1}\). Substitute into the integral and adjust the limits accordingly.
Evaluate the integral or determine convergence by analyzing the behavior of the integrand near the singularity and then proceed with integration techniques such as substitution or integration by parts if necessary.

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Improper Integrals

Improper integrals involve integration over an unbounded interval or integrands with unbounded behavior within the interval. To evaluate them, one often takes limits approaching the problematic points to determine convergence or divergence.
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Improper Integrals: Infinite Intervals

Behavior of the Integrand Near Singularities

Analyzing the integrand's behavior near points where it may become infinite or undefined is crucial. For example, if the denominator approaches zero, the integrand may have a singularity, affecting convergence of the integral.
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Completing the Square to Rewrite the Integrand

Substitution and Simplification Techniques

Using substitution can simplify the integral, especially when the integrand involves composite functions like exponentials. Simplifying the expression helps in identifying limits and evaluating the integral more easily.
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Substitution With an Extra Variable
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