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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.9.33

7–58. Improper integrals Evaluate the following integrals or state that they diverge.
33. ∫ (from 2 to ∞) 1/(y ln y) dy

Guida verificata passo dopo passo
1
Identify the type of integral: This is an improper integral because the upper limit of integration is infinity, so we need to evaluate \( \int_{2}^{\infty} \frac{1}{y \ln y} \, dy \).
Rewrite the integral as a limit: Express the improper integral as \( \lim_{t \to \infty} \int_{2}^{t} \frac{1}{y \ln y} \, dy \) to handle the infinite upper bound.
Use substitution to simplify the integral: Let \( u = \ln y \), then \( du = \frac{1}{y} dy \). This substitution transforms the integral into \( \int \frac{1}{u} du \).
Change the limits of integration according to the substitution: When \( y = 2 \), \( u = \ln 2 \); when \( y = t \), \( u = \ln t \). So the integral becomes \( \int_{\ln 2}^{\ln t} \frac{1}{u} du \).
Evaluate the integral and then take the limit: The integral \( \int \frac{1}{u} du \) is \( \ln |u| \), so evaluate \( \ln |u| \) from \( \ln 2 \) to \( \ln t \), then take the limit as \( t \to \infty \) to determine if the integral converges or diverges.

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Improper Integrals

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Integrals containing logarithmic functions often require substitution techniques, such as setting u = ln(y), to simplify the integral. Understanding the behavior of ln(y) and its derivative is crucial for correctly transforming and evaluating these integrals.
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