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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.1.20

7–64. Integration review Evaluate the following integrals.
20. ∫ eˣ (1 + eˣ)⁹ (1 - eˣ) dx

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Step 1: Begin by analyzing the integral ∫ eˣ (1 + eˣ)⁹ (1 - eˣ) dx. Notice that the integrand contains terms involving eˣ, (1 + eˣ), and (1 - eˣ). This suggests that substitution might simplify the expression.
Step 2: Let u = 1 + eˣ. Then, compute the derivative of u with respect to x: du/dx = eˣ. This implies that du = eˣ dx, which matches the eˣ dx term in the integral.
Step 3: Rewrite the integral in terms of u. Substituting u = 1 + eˣ, we also note that (1 - eˣ) can be expressed as (u - 2). The integral becomes ∫ (u⁹)(u - 2) du.
Step 4: Expand the integrand. Multiply u⁹ by (u - 2) to get u¹⁰ - 2u⁹. The integral now becomes ∫ (u¹⁰ - 2u⁹) du.
Step 5: Integrate term by term. Use the power rule for integration: ∫ uⁿ du = uⁿ⁺¹ / (n + 1). Apply this rule to each term in the expanded integrand to find the antiderivative. After integrating, substitute back u = 1 + eˣ to express the solution in terms of x.

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