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Ch.12 - Parametric and Polar Curves
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 12, Problema 12.R.72a

Parabola-hyperbola tangency: Let P be the parabola y = px² and H be the right half of the hyperbola x² - y² = 1.
a. For what value of p is P tangent to H?

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1
Start by writing down the equations of the two curves: the parabola \(P\) is given by \(y = p x^{2}\), and the hyperbola \(H\) is given by \(x^{2} - y^{2} = 1\) (considering only the right half, so \(x \geq 0\)).
Substitute the expression for \(y\) from the parabola into the hyperbola equation to find the points of intersection. This gives: \(x^{2} - (p x^{2})^{2} = 1\), which simplifies to \(x^{2} - p^{2} x^{4} = 1\).
Rewrite the equation as a polynomial in \(x^{2}\): \(p^{2} x^{4} - x^{2} + 1 = 0\). Let \(z = x^{2}\) to get \(p^{2} z^{2} - z + 1 = 0\).
For the parabola and hyperbola to be tangent, the equation must have exactly one solution for \(z\), meaning the quadratic in \(z\) has a single root. Set the discriminant of this quadratic to zero: \(\Delta = (-1)^{2} - 4 \cdot p^{2} \cdot 1 = 0\).
Solve the discriminant equation \(1 - 4 p^{2} = 0\) for \(p\) to find the value(s) of \(p\) where the parabola is tangent to the hyperbola.

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