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Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 2.8.84

Finding Limits of Differences When x → ±∞


Find the limits in Exercises 84–90. (Hint: Try multiplying and dividing by the conjugate.)


lim x → ∞ (√(x + 9) − √(x + 4))

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1
Identify the expression whose limit you need to find: \( \lim_{x \to \infty} (\sqrt{x + 9} - \sqrt{x + 4}) \).
To simplify the expression, multiply and divide by the conjugate: \( \frac{(\sqrt{x + 9} - \sqrt{x + 4})(\sqrt{x + 9} + \sqrt{x + 4})}{\sqrt{x + 9} + \sqrt{x + 4}} \).
The numerator becomes a difference of squares: \((x + 9) - (x + 4) = 5\).
The expression simplifies to \( \frac{5}{\sqrt{x + 9} + \sqrt{x + 4}} \).
As \( x \to \infty \), both \( \sqrt{x + 9} \) and \( \sqrt{x + 4} \) approach \( \sqrt{x} \), so the denominator approaches \( 2\sqrt{x} \). Thus, the limit becomes \( \lim_{x \to \infty} \frac{5}{2\sqrt{x}} \), which approaches 0.

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