Domanda del libro di testo
In Exercises 41–44, determine whether the piecewise-defined function is differentiable at x = 0.
g(x) = { x²/³, x ≥ 0
x¹/³, x < 0
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Ch. 3 - Derivatives
Hass15th EditionThomas' CalculusISBN: 9780137616077
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TOC.tableOfContents
- Ch. 1 - Functions155
- Ch. 2 - Limits and Continuity240
- Ch. 3 - Derivatives337
- Ch. 4 - Applications of Derivatives293
- Ch. 5 - Integrals41
- Ch. 6 - Applications of Definite Integrals25
- Ch. 7 - Transcendental Functions490
- Ch. 8 - Techniques of Integration399
- Ch. 9 - First-Order Differential Equations66
- Ch. 10 - Infinite Sequences and Series132
- Ch. 11 - Parametric Equations and Polar Coordinates58
Capitolo 3, Problema 3.21
Find the derivatives of the functions in Exercises 1–42.
𝔂 = 1 x² csc 2
2 x
Guida verificata passo dopo passo1
Step 1: Identify the function components. The given function is \( y = \frac{1}{x^2} \csc(2x) \). This is a product of two functions: \( u(x) = \frac{1}{x^2} \) and \( v(x) = \csc(2x) \).
Step 2: Apply the product rule for differentiation. The product rule states that if \( y = u(x) \cdot v(x) \), then \( y' = u'(x) \cdot v(x) + u(x) \cdot v'(x) \).
Step 3: Differentiate \( u(x) = \frac{1}{x^2} \). Use the power rule: \( u'(x) = -2x^{-3} \).
Step 4: Differentiate \( v(x) = \csc(2x) \). Use the chain rule: \( v'(x) = -2 \csc(2x) \cot(2x) \).
Step 5: Substitute \( u'(x) \), \( v(x) \), \( u(x) \), and \( v'(x) \) into the product rule formula to find \( y' \).
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Derivatives
The derivative of a function measures how the function's output value changes as its input value changes. It is a fundamental concept in calculus, representing the slope of the tangent line to the curve of the function at any given point. Derivatives can be computed using various rules, such as the power rule, product rule, and quotient rule, depending on the form of the function.
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Derivatives
Cosecant Function (csc)
The cosecant function, denoted as csc(x), is the reciprocal of the sine function, defined as csc(x) = 1/sin(x). It is important in calculus when dealing with trigonometric functions, especially when finding derivatives. Understanding how to differentiate csc(x) and its properties is essential for solving problems involving trigonometric derivatives.
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6:22Graphs of Secant and Cosecant Functions
Quotient Rule
The quotient rule is a method for finding the derivative of a function that is the ratio of two other functions. If you have a function defined as f(x) = g(x)/h(x), the derivative is given by f'(x) = (g'(x)h(x) - g(x)h'(x)) / (h(x))². This rule is crucial when differentiating functions that involve division, such as the one presented in the question.
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