Ch. 3 - Derivatives

Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo

Hass 15th Edition

Ch. 3 - Derivatives

Problema 3.2.39

Capitolo 3, Problema 3.2.39

One-Sided Derivatives

Compute the right-hand and left-hand derivatives as limits to show that the functions in Exercises 37–40 are not differentiable at the point P.

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Identify the function and the point of interest: The function is piecewise, with \( y = \sqrt{x} \) for \( x < 1 \) and \( y = 2x - 1 \) for \( x \geq 1 \). The point of interest is \( P(1, 1) \).

Compute the left-hand derivative at \( x = 1 \): Use the definition of the derivative as a limit. For \( x < 1 \), the function is \( y = \sqrt{x} \). The left-hand derivative is \( \lim_{{h \to 0^-}} \frac{\sqrt{1+h} - 1}{h} \).

Compute the right-hand derivative at \( x = 1 \): For \( x \geq 1 \), the function is \( y = 2x - 1 \). The right-hand derivative is \( \lim_{{h \to 0^+}} \frac{(2(1+h) - 1) - 1}{h} \).

Evaluate the left-hand limit: Simplify the expression \( \frac{\sqrt{1+h} - 1}{h} \) using algebraic manipulation, such as multiplying by the conjugate, to find the limit as \( h \to 0^- \).

Evaluate the right-hand limit: Simplify the expression \( \frac{2h}{h} \) to find the limit as \( h \to 0^+ \). Compare the left-hand and right-hand derivatives to determine if they are equal.

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One-Sided Derivatives

One-sided derivatives are limits that evaluate the behavior of a function as it approaches a specific point from one side only. The right-hand derivative considers the limit as the input approaches the point from the right, while the left-hand derivative considers the limit from the left. If these two limits exist but are not equal, the function is not differentiable at that point.

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05:50

One-Sided Limits

Differentiability

A function is differentiable at a point if it has a defined derivative at that point, which means the function must be continuous and have a unique tangent line. If the left-hand and right-hand derivatives at a point are not equal, the function is not differentiable there. This concept is crucial for understanding the smoothness and behavior of functions at specific points.

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Percorso guidato

05:53

Finding Differentials

Limits

Limits are fundamental in calculus, representing the value that a function approaches as the input approaches a certain point. They are essential for defining derivatives, as the derivative itself is the limit of the average rate of change of the function as the interval shrinks to zero. Understanding limits allows for the analysis of function behavior near points of interest, particularly in determining continuity and differentiability.

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One-Sided Limits

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Slopes and Tangent Lines

In Exercises 1–4, use the grid and a straight edge to make a rough estimate of the slope of the curve (in y-units per x-unit) at the points P₁ and P₂.

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Cylinder pressure If gas in a cylinder is maintained at a constant temperature T, the pressure P is related to the volume V by a formula of the form

P = (nRT / (V − nb)) − (an² / V²),

in which a, b, n, and R are constants. Find dP/dV. (See accompanying figure.)

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Find the derivatives of the functions in Exercises 19–40.

g(t) = (1 + sin(3t) / (3 − 2t))⁻¹

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Domanda del libro di testo

Find the derivatives of the functions in Exercises 19–40.