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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.7.58

Checking Antiderivative Formulas


Verify the formulas in Exercises 57–62 by differentiation.


∫(3x + 5)⁻² dx = −(3x + 5)⁻¹/3 + C

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1
Identify the given antiderivative formula: \(\int (3x + 5)^{-2} \, dx = -\frac{(3x + 5)^{-1}}{3} + C\).
To verify this formula, differentiate the right-hand side expression \(-\frac{(3x + 5)^{-1}}{3} + C\) with respect to \(x\).
Apply the chain rule for differentiation: if \(f(x) = (3x + 5)^{-1}\), then \(f'(x) = -1 \cdot (3x + 5)^{-2} \cdot 3\) because the derivative of the inside function \(3x + 5\) is 3.
Multiply the derivative by the constant factor \(-\frac{1}{3}\) outside the function, simplifying the expression step-by-step.
Confirm that the resulting derivative simplifies exactly to the original integrand \((3x + 5)^{-2}\), which verifies the antiderivative formula.

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