Skip to main content
Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.1.9

Finding Extrema from Graphs


In Exercises 7–10, find the absolute extreme values and where they occur.


Graph showing a line segment from point (2, 0) to point (2, 5) on a coordinate plane, indicating extrema.

Guida verificata passo dopo passo
1
Identify the endpoints of the graph. The graph starts at the point (0, 5) and ends at the point (2, 0).
Determine the type of extrema by analyzing the graph. The graph is a straight line decreasing from (0, 5) to (2, 0).
The absolute maximum value occurs at the highest point on the graph, which is at (0, 5).
The absolute minimum value occurs at the lowest point on the graph, which is at (2, 0).
Verify that there are no other points on the graph that exceed the y-values at the endpoints, confirming the absolute extrema.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Absolute Extrema

Absolute extrema refer to the highest or lowest points on a graph over a given interval. The absolute maximum is the highest point, while the absolute minimum is the lowest. These points can occur at critical points or endpoints of the interval. In the context of the graph, identifying these points involves examining the y-values at the endpoints and any critical points within the interval.
Video consigliato:
05:58
Finding Extrema Graphically

Endpoints of a Graph

Endpoints are the points at the boundaries of a graph's domain. They are crucial when determining absolute extrema, as extrema can occur at these points. In the given graph, the endpoints are at (2, 5) and (2, 0). Evaluating the function's value at these points helps in identifying the absolute maximum and minimum values.
Video consigliato:
Percorso guidato
06:15
Graphing The Derivative

Critical Points

Critical points are where the derivative of a function is zero or undefined, indicating potential local maxima or minima. However, in a linear segment like the one shown, there are no critical points within the interval, as the slope is constant. Thus, for this graph, the focus is on the endpoints to find the absolute extrema.
Video consigliato:
04:50
Critical Points
Pratica correlata
Domanda del libro di testo

A cone is formed from a circular piece of material of radius 1 meter by removing a section of angle θ and then joining the two straight edges. Determine the largest possible volume for the cone.

245
views
Domanda del libro di testo

Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫x⁻¹ᐟ³ dx

23
views
Domanda del libro di testo

Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫(8y − 2 / y¹ᐟ⁴) dy

19
views
Domanda del libro di testo

Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫(1 + tan²θ)dθ (Hint:1 + tan²θ = sec²θ)

37
views
Domanda del libro di testo

Roots (Zeros)


Show that the functions in Exercises 19–26 have exactly one zero in the given interval.


f(x) = x⁴ + 3x + 1, [−2, −1]

243
views
Domanda del libro di testo

Absolute Extrema on Finite Closed Intervals


In Exercises 21–36, find the absolute maximum and minimum values of each function on the given interval. Then graph the function. Identify the points on the graph where the absolute extrema occur, and include their coordinates.


h(x) = ³√x, −1 ≤ x ≤ 8

204
views