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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.PE.90

Initial Value Problems
Solve the initial value problems in Exercises 89–92.


dy/dx = (𝓍 + 1/𝓍)² , y(1)= 1

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Rewrite the differential equation clearly: \(\frac{dy}{dx} = \left(x + \frac{1}{x}\right)^2\).
Expand the right-hand side expression: \(\left(x + \frac{1}{x}\right)^2 = x^2 + 2 + \frac{1}{x^2}\).
Set up the integral to find \(y\): \(y = \int \left(x^2 + 2 + \frac{1}{x^2}\right) \, dx + C\).
Integrate each term separately: \(\int x^2 \, dx\), \(\int 2 \, dx\), and \(\int \frac{1}{x^2} \, dx\).
Use the initial condition \(y(1) = 1\) to solve for the constant of integration \(C\) after finding the general solution.

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