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Ch. 5 - Integrals
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 5.PE.10d

If ∫₀² ƒ(x) dx = π, ∫₀² 7g(x) dx = 7, and ∫₀¹ g(x) dx = 2, find the value of each of the following.
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d. ∫₀² √2ƒ(x) dx

Guida verificata passo dopo passo
1
Identify the given integral and the constant multiplier: the integral to find is \(\int_0^2 \sqrt{2} f(x) \, dx\).
Recall the property of integrals that allows constants to be factored out: \(\int_a^b c \cdot h(x) \, dx = c \int_a^b h(x) \, dx\) where \(c\) is a constant.
Apply this property to the integral: \(\int_0^2 \sqrt{2} f(x) \, dx = \sqrt{2} \int_0^2 f(x) \, dx\).
Use the given value \(\int_0^2 f(x) \, dx = \pi\) and substitute it into the expression: \(\sqrt{2} \times \pi\).
Express the final answer as \(\sqrt{2} \pi\), which represents the value of the integral \(\int_0^2 \sqrt{2} f(x) \, dx\).

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Definite Integral and Linearity

The definite integral represents the net area under a curve between two points. It is linear, meaning constants can be factored out: ∫a^b c·f(x) dx = c·∫a^b f(x) dx. This property allows simplification when integrating scaled functions.
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