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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.8.3a

3. Which of the following functions grow faster than x² as x→∞? Which grow at the same rate as x²? Which grow slower?
a. x² + 4x

Guida verificata passo dopo passo
1
Identify the dominant term in the function as \( x \to \infty \). For the function \( f(x) = x^2 + 4x \), the dominant term is \( x^2 \) because it grows faster than \( 4x \) when \( x \) becomes very large.
Compare the growth rate of \( f(x) \) to \( x^2 \) by considering the ratio \( \frac{f(x)}{x^2} = \frac{x^2 + 4x}{x^2} \).
Simplify the ratio: \( \frac{x^2 + 4x}{x^2} = 1 + \frac{4}{x} \).
Analyze the limit of the ratio as \( x \to \infty \): \( \lim_{x \to \infty} \left(1 + \frac{4}{x}\right) = 1 \). This means \( f(x) \) grows at the same rate as \( x^2 \).
Conclude that \( x^2 + 4x \) grows at the same rate as \( x^2 \) because the lower order term \( 4x \) becomes insignificant compared to \( x^2 \) for large \( x \).

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