Skip to main content
Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.2.47

Evaluate the integrals in Exercises 39–56.
47. ∫(from 2 to 4)dx/(x(ln x)²)

Guida verificata passo dopo passo
1
Identify the integral to be evaluated: \(\int_{2}^{4} \frac{dx}{x (\ln x)^2}\).
Recognize that the integrand involves \(x\) and \(\ln x\), suggesting a substitution related to \(\ln x\).
Let \(u = \ln x\). Then, compute \(du\): since \(u = \ln x\), we have \(du = \frac{1}{x} dx\), which implies \(dx = x \, du\).
Rewrite the integral in terms of \(u\): substitute \(dx\) and \(x\) accordingly. The integral becomes \(\int_{u=\ln 2}^{u=\ln 4} \frac{x \, du}{x u^2} = \int_{\ln 2}^{\ln 4} \frac{du}{u^2}\).
Now, integrate \(\int \frac{1}{u^2} du = \int u^{-2} du\). Use the power rule for integration to find the antiderivative, then apply the limits \(u=\ln 2\) to \(u=\ln 4\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
3m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Integration of Rational Functions

This involves integrating functions expressed as ratios of polynomials or other expressions. Recognizing the form helps in choosing appropriate techniques such as substitution or partial fractions to simplify the integral.
Video consigliato:
6:04
Intro to Rational Functions

Substitution Method

A technique where a part of the integral is replaced with a new variable to simplify the integral. For example, substituting u = ln(x) transforms the integral into a more manageable form involving u.
Video consigliato:
07:33
Euler's Method

Properties of the Natural Logarithm

Understanding the behavior and derivatives of ln(x) is crucial. Since d/dx(ln x) = 1/x, this relationship often guides substitution choices and helps simplify integrals involving ln(x).
Video consigliato:
05:36
Change of Base Property