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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.2.6

In Exercises 5 and 6, solve for t.
6. ln(t-2) = ln8 - ln(t)

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Start with the given equation: \(\ln(t - 2) = \ln 8 - \ln t\).
Use the logarithm property that \(\ln a - \ln b = \ln \left( \frac{a}{b} \right)\) to combine the right side: \(\ln(t - 2) = \ln \left( \frac{8}{t} \right)\).
Since the natural logarithm function \(\ln x\) is one-to-one, set the arguments equal to each other: \(t - 2 = \frac{8}{t}\).
Multiply both sides of the equation by \(t\) to eliminate the denominator: \(t(t - 2) = 8\).
Expand and rearrange the equation into standard quadratic form: \(t^2 - 2t - 8 = 0\). Then solve this quadratic equation for \(t\).

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