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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.1.67c

In Exercises 67–72, you will explore some functions and their inverses together with their derivatives and tangent line approximations at specified points. Perform the following steps using your CAS:
c. Find the equation for the tangent line to f at the specified point (x_0, f(x_0)).
67. y= √(3x-2), 2/3 ≤ x ≤ 4, x_0=3

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1
Identify the function given: \(y = \sqrt{3x - 2}\), and the point at which to find the tangent line is \(x_0 = 3\).
Calculate the value of the function at \(x_0\): find \(f(3) = \sqrt{3(3) - 2} = \sqrt{9 - 2}\) to get the point \((3, f(3))\) on the curve.
Find the derivative of the function \(f(x)\) to get the slope of the tangent line. Use the chain rule: \(f(x) = (3x - 2)^{1/2}\), so \(f'(x) = \frac{1}{2}(3x - 2)^{-1/2} \times 3\).
Evaluate the derivative at \(x_0 = 3\) to find the slope of the tangent line: \(m = f'(3)\).
Use the point-slope form of the line equation with the point \((3, f(3))\) and slope \(m\): \(y - f(3) = m(x - 3)\) to write the equation of the tangent line.

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