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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.3.9

In Exercises 7–26, find the derivative of y with respect to x, t, or θ, as appropriate.
y = e^(5-7x)

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1
Identify the function given: \(y = e^{5 - 7x}\). This is an exponential function where the exponent is a linear expression in \(x\).
Recall the chain rule for differentiation: if \(y = e^{u(x)}\), then \(\frac{dy}{dx} = e^{u(x)} \cdot \frac{du}{dx}\), where \(u(x)\) is the exponent function.
Set \(u(x) = 5 - 7x\). Next, find the derivative of \(u(x)\) with respect to \(x\): \(\frac{du}{dx} = -7\).
Apply the chain rule by multiplying the original function by the derivative of the exponent: \(\frac{dy}{dx} = e^{5 - 7x} \cdot (-7)\).
Write the final expression for the derivative as \(\frac{dy}{dx} = -7 e^{5 - 7x}\) (do not simplify further if not required).

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The chain rule is a method for differentiating composite functions. It states that the derivative of f(g(x)) is f'(g(x)) times g'(x). This is essential when the exponent itself is a function of x, like 5 - 7x in this problem.
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