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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.3.11

In Exercises 7–26, find the derivative of y with respect to x, t, or θ, as appropriate.
y = xe^x-e^x

Guida verificata passo dopo passo
1
Identify the function given: \(y = xe^x - e^x\).
Recognize that the function is composed of two terms: \(xe^x\) and \(-e^x\), and you will need to differentiate each term separately.
For the first term \(xe^x\), apply the product rule for differentiation, which states: \(\frac{d}{dx}[u v] = u' v + u v'\). Here, let \(u = x\) and \(v = e^x\).
Calculate the derivatives of \(u\) and \(v\): \(u' = \frac{d}{dx}[x] = 1\) and \(v' = \frac{d}{dx}[e^x] = e^x\).
Apply the product rule to the first term: \(\frac{d}{dx}[xe^x] = 1 \cdot e^x + x \cdot e^x = e^x + xe^x\). Then differentiate the second term \(-e^x\) as \(-e^x\). Finally, combine these results to write the derivative of \(y\).

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