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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoHass 15th EditionCh. 7 - Transcendental FunctionsProblema 7.2.14
Capitolo 7, Problema 7.2.14

In Exercises 7–38, find the derivative of y with respect to x, t, or θ, as appropriate.
14. y = ln(2θ+2)

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Identify the function given: \(y = \ln(2\theta + 2)\), where \(y\) is expressed in terms of \(\theta\).
Recall the derivative rule for the natural logarithm function: if \(y = \ln(u)\), then \(\frac{dy}{d\theta} = \frac{1}{u} \cdot \frac{du}{d\theta}\).
Set \(u = 2\theta + 2\) and find its derivative with respect to \(\theta\): \(\frac{du}{d\theta} = 2\).
Apply the chain rule by substituting \(u\) and \(\frac{du}{d\theta}\) into the derivative formula: \(\frac{dy}{d\theta} = \frac{1}{2\theta + 2} \cdot 2\).
Simplify the expression if possible to write the derivative in its simplest form.

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Derivative of the Natural Logarithm Function

The derivative of ln(u), where u is a differentiable function of a variable, is given by (1/u) times the derivative of u. This rule allows us to differentiate logarithmic functions by applying the chain rule to the inner function.
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Derivative of the Natural Logarithmic Function

Chain Rule

The chain rule is used to differentiate composite functions. It states that the derivative of a function composed of another function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
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Intro to the Chain Rule

Differentiation with Respect to a Variable

When differentiating, it is important to identify the variable with respect to which the derivative is taken. In this problem, the variable is θ, so all derivatives must be computed considering θ as the independent variable.
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Separation of Variables
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