Skip to main content
Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.2.23

In Exercises 7–38, find the derivative of y with respect to x, t, or θ, as appropriate.
23. y = ln(x)/(1+ln(x))

Guida verificata passo dopo passo
1
Identify the function given: \(y = \frac{\ln(x)}{1 + \ln(x)}\). We need to find \(\frac{dy}{dx}\) since the variable is \(x\).
Recognize that this is a quotient of two functions: numerator \(u = \ln(x)\) and denominator \(v = 1 + \ln(x)\).
Recall the quotient rule for derivatives: \(\frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \cdot u' - u \cdot v'}{v^2}\).
Compute the derivatives of numerator and denominator separately: \(u' = \frac{d}{dx} \ln(x) = \frac{1}{x}\) and \(v' = \frac{d}{dx} (1 + \ln(x)) = \frac{1}{x}\).
Substitute \(u\), \(v\), \(u'\), and \(v'\) into the quotient rule formula to express \(\frac{dy}{dx}\) as \(\frac{(1 + \ln(x)) \cdot \frac{1}{x} - \ln(x) \cdot \frac{1}{x}}{(1 + \ln(x))^2}\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Derivative of the Natural Logarithm Function

The derivative of ln(x) with respect to x is 1/x. This fundamental rule is essential when differentiating expressions involving natural logarithms, as it allows us to handle the logarithmic part of the function accurately.
Video consigliato:
05:18
Derivative of the Natural Logarithmic Function

Quotient Rule

The quotient rule is used to differentiate functions expressed as one function divided by another. It states that the derivative of f(x)/g(x) is (g(x)f'(x) - f(x)g'(x)) / [g(x)]², which is crucial for differentiating y = ln(x) / (1 + ln(x)).
Video consigliato:
06:43
The Quotient Rule

Chain Rule

The chain rule helps differentiate composite functions by multiplying the derivative of the outer function by the derivative of the inner function. It is important here because ln(x) appears inside another function, requiring careful application of this rule.
Video consigliato:
05:02
Intro to the Chain Rule