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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.8.92

92. Evaluate ∫ from 3 to ∞ [ dx / (x √(x² - 9))]

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Recognize that the integral is an improper integral because the upper limit is infinity. So, rewrite the integral as a limit: \(\displaystyle \lim_{t \to \infty} \int_{3}^{t} \frac{dx}{x \sqrt{x^{2} - 9}}\).
To evaluate the integral \(\int \frac{dx}{x \sqrt{x^{2} - 9}}\), use a trigonometric substitution. Since the integrand contains \(\sqrt{x^{2} - 9}\), let \(x = 3 \sec \theta\), which implies \(dx = 3 \sec \theta \tan \theta \, d\theta\).
Substitute \(x = 3 \sec \theta\) and \(dx\) into the integral. Also, express \(\sqrt{x^{2} - 9}\) in terms of \(\theta\): \(\sqrt{(3 \sec \theta)^{2} - 9} = \sqrt{9 \sec^{2} \theta - 9} = 3 \tan \theta\).
Rewrite the integral in terms of \(\theta\): \(\int \frac{3 \sec \theta \tan \theta \, d\theta}{3 \sec \theta \cdot 3 \tan \theta}\). Simplify the expression by canceling common factors.
After simplification, integrate the resulting expression with respect to \(\theta\). Then, convert back to the variable \(x\) using the inverse trigonometric relationships from the substitution. Finally, apply the limits by converting the original limits \(x=3\) and \(x=t\) to their corresponding \(\theta\) values, and take the limit as \(t \to \infty\).

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