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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.4.8

Evaluate the integrals in Exercises 1–14.
∫ √(1 - 9t²) dt

Guida verificata passo dopo passo
1
Recognize that the integral \( \int \sqrt{1 - 9t^2} \, dt \) resembles the form \( \int \sqrt{a^2 - u^2} \, du \), which suggests using a trigonometric substitution to simplify the square root expression.
Set the substitution \( u = 3t \), so that \( u^2 = 9t^2 \). Then, rewrite the integral in terms of \( u \): \( \int \sqrt{1 - u^2} \cdot \frac{du}{3} \). This simplifies the integral to \( \frac{1}{3} \int \sqrt{1 - u^2} \, du \).
Use the trigonometric substitution \( u = \sin \theta \), which implies \( du = \cos \theta \, d\theta \). This transforms the integral into \( \frac{1}{3} \int \sqrt{1 - \sin^2 \theta} \cdot \cos \theta \, d\theta \).
Simplify the square root using the Pythagorean identity: \( \sqrt{1 - \sin^2 \theta} = \cos \theta \). The integral becomes \( \frac{1}{3} \int \cos \theta \cdot \cos \theta \, d\theta = \frac{1}{3} \int \cos^2 \theta \, d\theta \).
Use the power-reduction formula for \( \cos^2 \theta \): \( \cos^2 \theta = \frac{1 + \cos 2\theta}{2} \). Substitute this into the integral and integrate with respect to \( \theta \). After integrating, substitute back \( \theta = \arcsin u \) and then \( u = 3t \) to express the answer in terms of \( t \).

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Trigonometric Substitution

Trigonometric substitution is a technique used to evaluate integrals involving square roots of quadratic expressions. By substituting a trigonometric function for the variable, the integral simplifies using trigonometric identities. For example, for integrals with √(a² - x²), substituting x = a sin(θ) helps transform the integral into a trigonometric form.
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Integration of Trigonometric Functions

After substitution, the integral often involves trigonometric functions like sine and cosine. Understanding how to integrate these functions, including using identities and standard integral formulas, is essential. This allows the integral to be evaluated in terms of θ before converting back to the original variable.
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Back-Substitution

Once the integral is evaluated in terms of the trigonometric variable, back-substitution replaces the trigonometric expression with the original variable. This step uses the initial substitution relationship and trigonometric identities to express the final answer in terms of the original variable t.
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