Skip to main content
Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.2.26

Evaluate the integrals in Exercises 25–30 by using a substitution prior to integration by parts.
∫ from 0 to 1 x√(1 - x) dx

Guida verificata passo dopo passo
1
Identify the integral to solve: \(\int_0^1 x \sqrt{1 - x} \, dx\).
Use substitution to simplify the integral. Let \(u = 1 - x\), which implies $du = -dx$ and \(x = 1 - u\).
Change the limits of integration according to the substitution: when \(x = 0\), \(u = 1\); when \(x = 1\), \(u = 0\).
Rewrite the integral in terms of \(u\): \(\int_1^0 (1 - u) \sqrt{u} (-du)\), then reverse the limits to get rid of the negative sign, resulting in \(\int_0^1 (1 - u) \sqrt{u} \, du\).
Expand the integrand to \(\int_0^1 (1 - u) u^{1/2} \, du = \int_0^1 (u^{1/2} - u^{3/2}) \, du\), and then integrate term-by-term.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Substitution Method

The substitution method simplifies integrals by changing variables to transform the integral into a more manageable form. It involves choosing a substitution u = g(x) that simplifies the integrand, then rewriting the integral in terms of u and du. This technique is especially useful when the integral contains a composite function.
Video consigliato:
07:33
Euler's Method

Integration by Parts

Integration by parts is a technique based on the product rule for differentiation. It transforms the integral of a product of functions into simpler integrals using the formula ∫u dv = uv - ∫v du. Choosing u and dv wisely is key to simplifying the integral effectively.
Video consigliato:
Percorso guidato
06:18
Integration by Parts for Definite Integrals

Definite Integrals and Limits of Integration

Definite integrals calculate the net area under a curve between two points, using specified limits of integration. When performing substitution, the limits must be adjusted to the new variable or the integral must be converted back to the original variable before evaluating. Proper handling of limits ensures accurate evaluation of the integral.
Video consigliato:
Percorso guidato
05:43
Definition of the Definite Integral