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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.8.24

The integrals in Exercises 1–34 converge. Evaluate the integrals without using tables.
∫₋∞^∞ 2x e^(−x²) dx

Guida verificata passo dopo passo
1
Recognize that the integral is an improper integral over the entire real line, from \(-\infty\) to \(\infty\), of the function \(2x e^{-x^{2}}\).
Note that the integrand \(2x e^{-x^{2}}\) is an odd function because \(2(-x) e^{-(-x)^{2}} = -2x e^{-x^{2}}\), which is the negative of the original function.
Recall that the integral of any odd function over symmetric limits \([-a, a]\) is zero, provided the integral converges.
Since the limits are \(-\infty\) to \(\infty\), which are symmetric about zero, and the function is odd and integrable, the integral evaluates to zero.
Therefore, without performing any integration by parts or substitution, conclude that the value of the integral is zero due to the symmetry of the integrand.

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