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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.4.18

Use any method to evaluate the integrals in Exercises 15–38. Most will require trigonometric substitutions, but some can be evaluated by other methods.
∫ dx / √(1 - x²)

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Recognize that the integral \( \int \frac{dx}{\sqrt{1 - x^2}} \) resembles the derivative of an inverse trigonometric function, specifically \( \arcsin x \) or \( \arccos x \).
Recall the derivative formula: \( \frac{d}{dx} \arcsin x = \frac{1}{\sqrt{1 - x^2}} \). This suggests that the integral is related to \( \arcsin x \).
Set up the integral using the substitution method if needed, but in this case, direct recognition is sufficient since the integrand matches the derivative of \( \arcsin x \).
Write the integral as \( \int \frac{dx}{\sqrt{1 - x^2}} = \arcsin x + C \), where \( C \) is the constant of integration.
Verify the result by differentiating \( \arcsin x + C \) to confirm it returns the original integrand \( \frac{1}{\sqrt{1 - x^2}} \).

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Trigonometric Substitution

Trigonometric substitution is a technique used to simplify integrals involving square roots of expressions like 1 - x² by substituting x with a trigonometric function such as sin(θ). This transforms the integral into a trigonometric integral that is easier to evaluate.
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Inverse Trigonometric Functions

Integrals involving expressions like 1/√(1 - x²) often result in inverse trigonometric functions, specifically arcsin(x). Recognizing this form helps directly identify the antiderivative without complex manipulation.
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Derivatives of Other Inverse Trigonometric Functions

Basic Integration Techniques

Understanding fundamental integration rules and recognizing standard integral forms allows for efficient evaluation. For example, knowing that ∫ dx/√(1 - x²) = arcsin(x) + C avoids unnecessary steps.
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