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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.6.12

Use the table of integrals at the back of the text to evaluate the integrals in Exercises 1–26.
∫ dx / (x √(7 - x²))

Guida verificata passo dopo passo
1
Recognize that the integral has the form \(\int \frac{dx}{x \sqrt{a - x^2}}\), where \(a = 7\). This suggests using a standard integral formula involving expressions of the form \(\frac{1}{x \sqrt{a - x^2}}\).
Recall from the table of integrals that \(\int \frac{dx}{x \sqrt{a - x^2}}\) can be evaluated using a substitution or a known formula, often involving inverse trigonometric or logarithmic functions.
Consider the substitution \(x = \sqrt{7} \sin \theta\), which simplifies the square root term: \(\sqrt{7 - x^2} = \sqrt{7 - 7 \sin^2 \theta} = \sqrt{7} \cos \theta\). This substitution will help rewrite the integral in terms of \(\theta\).
Rewrite \(dx\) in terms of \(d\theta\): since \(x = \sqrt{7} \sin \theta\), then \(dx = \sqrt{7} \cos \theta \, d\theta\). Substitute \(x\), \(dx\), and \(\sqrt{7 - x^2}\) into the integral to express it entirely in terms of \(\theta\).
Simplify the integral after substitution and then integrate with respect to \(\theta\). Finally, revert back to the variable \(x\) using the inverse substitution \(\theta = \arcsin \left( \frac{x}{\sqrt{7}} \right)\) to express the answer in terms of \(x\).

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