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Ch. 9 - First-Order Differential Equations
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 9.PE.1

In Exercises 1–22, solve the differential equation.
y' = xeʸ√(x-2)

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1
Rewrite the given differential equation as \(\frac{dy}{dx} = x e^{y} \sqrt{x - 2}\) to clearly identify the variables and their derivatives.
Separate the variables by dividing both sides by \(e^{y}\) and multiplying both sides by \(dx\), giving \(e^{-y} dy = x \sqrt{x - 2} \, dx\).
Integrate both sides separately: integrate $e^{-y} dy$ with respect to \(y\) on the left side, and integrate \(x \sqrt{x - 2} \, dx\) with respect to \(x\) on the right side.
For the right side integral, consider using a substitution such as \(u = x - 2\) to simplify the integral \(\int x \sqrt{x - 2} \, dx\).
After integrating both sides, include the constant of integration \(C\) and solve for \(y\) if possible to express the general solution.

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