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Ch. 2 - Functions and Graphs
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 67

In Exercises 67-74, find a. (fog) (x) b. the domain of f o g. f(x) = 2/(x+3), g(x) = 1/x

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Step 1: Understand the composition of functions. The notation (fog)(x) represents the composition of f and g, meaning f(g(x)). To find this, substitute g(x) into f(x).
Step 2: Substitute g(x) = 1/x into f(x) = 2/(x+3). Replace every instance of 'x' in f(x) with g(x). This gives f(g(x)) = 2/((1/x) + 3).
Step 3: Simplify the expression for f(g(x)). Combine the terms in the denominator ((1/x) + 3) by finding a common denominator. This results in f(g(x)) = 2/(1/x + 3) = 2/((1 + 3x)/x).
Step 4: Further simplify f(g(x)) by dividing 2 by the fraction (1 + 3x)/x. This results in f(g(x)) = 2x/(1 + 3x).
Step 5: Determine the domain of f o g. The domain is the set of all x-values for which the composition is defined. For f(g(x)) = 2x/(1 + 3x), ensure that the denominator (1 + 3x) ≠ 0 and g(x) = 1/x is defined (x ≠ 0). Therefore, the domain excludes x = 0 and x = -1/3.

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