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How many atoms are present in 6.25 moles of chromium (Cr)?
A
3.76 × 10^{24} atoms
B
9.98 × 10^{22} atoms
C
1.04 × 10^{25} atoms
D
6.02 × 10^{23} atoms
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1
Identify the quantity given: 6.25 moles of chromium (Cr).
Recall that 1 mole of any substance contains Avogadro's number of particles (atoms, in this case), which is \(6.022 \times 10^{23}\) atoms/mole.
Set up the calculation to find the total number of atoms by multiplying the number of moles by Avogadro's number: \(\text{Number of atoms} = 6.25 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole}\).
Perform the multiplication of the numerical values and combine the powers of ten accordingly to express the answer in scientific notation.
Interpret the result as the total number of chromium atoms present in 6.25 moles.