Scelta multipla
Which of the following solutions contains the largest number of chloride ions?
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6. Chemical Quantities & Aqueous Reactions
Molarity
Scelta multipla
How many grams (g) of NaCl are required to prepare 250 mL of 0.80 M NaCl solution? (Answer to 2 decimal places.)
A
18.00 g
B
8.00 g
C
11.68 g
D
4.68 g
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Identify the given information: volume of solution (V) = 250 mL, molarity (M) = 0.80 M, and the solute is NaCl.
Convert the volume from milliliters to liters because molarity is expressed in moles per liter: \(V (L) = \frac{250}{1000}\).
Use the molarity formula to find the number of moles of NaCl needed: \(\text{moles} = M \times V (L)\).
Calculate the molar mass of NaCl by adding the atomic masses of sodium (Na) and chlorine (Cl): \(\text{molar mass of NaCl} = 22.99 + 35.45\) g/mol.
Convert moles of NaCl to grams using the molar mass: \(\text{mass} = \text{moles} \times \text{molar mass}\).
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