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Which of the following are the valence electrons for tellurium (Te)?
A
4s^2 4p^6
B
5s^2 4d^{10}
C
5s^2 5p^4
D
6s^2 6p^4
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1
Identify the atomic number of tellurium (Te), which is 52, to understand its electron configuration.
Recall that valence electrons are the electrons in the outermost principal energy level (highest n value) of an atom.
Write the full electron configuration of tellurium, filling orbitals in order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, etc., until you reach 52 electrons.
Determine the highest principal quantum number (n) in the configuration; for tellurium, this is n=5, so the valence electrons are those in the 5s and 5p orbitals.
Identify the number of electrons in the 5s and 5p orbitals, which correspond to the valence electrons, and confirm that the correct valence electron configuration is \$5s^2 5p^4$.