Scelta multipla
Which of the following combinations of principal quantum number n and angular momentum quantum number l is impossible?
110
views
9. Quantum Mechanics
Quantum Numbers: Angular Momentum Quantum Number
Scelta multipla
For the principal quantum number n = 5, how many possible values can the angular momentum quantum number l have?
A
1
B
6
C
5
D
4
Guida verificata passo dopo passo1
Recall that the principal quantum number \(n\) determines the energy level and can take positive integer values: \(n = 1, 2, 3, \ldots\).
The angular momentum quantum number \(l\) depends on \(n\) and can take integer values from \(0\) up to \(n-1\).
For \(n = 5\), the possible values of \(l\) are \$0, 1, 2, 3,$ and \(4\).
Count the number of possible \(l\) values: since \(l\) ranges from \(0\) to \(4\), there are \(5\) possible values.
Therefore, the number of possible values for the angular momentum quantum number \(l\) when \(n = 5\) is \(5\).
Video correlati
Pratica correlata
