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How many double bonds are present in the Lewis dot structure of the neutral compound hydrogen fluoride (HF)?
A
0
B
2
C
3
D
1
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1
Identify the atoms involved in the molecule: hydrogen (H) and fluorine (F).
Determine the number of valence electrons for each atom: hydrogen has 1 valence electron, fluorine has 7 valence electrons.
Recall that hydrogen can form only one single bond because it needs only 2 electrons to complete its valence shell (duet rule).
Draw the Lewis structure by placing a single bond (a pair of shared electrons) between H and F, and then complete fluorine's octet with lone pairs of electrons.
Count the number of double bonds in the structure; since hydrogen forms only a single bond and fluorine completes its octet with lone pairs, there are no double bonds in HF.