Scelta multipla
What is the equilibrium constant expression (K) for the reaction: 2 H_2(g) + O_2(g)
ightleftharpoons 2 H_2O(g)?
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16. Chemical Equilibrium
Equilibrium Constant K
Scelta multipla
Given the reaction: N_2(g) + 3H_2(g) ightleftharpoons 2NH_3(g), the equilibrium constant K for this reaction is:
A
K = [NH_3]^2 / ([N_2][H_2]^3)
B
K = [NH_3] / ([N_2][H_2])
C
K = [N_2][H_2]^3 / [NH_3]^2
D
K = [N_2][H_2] / [NH_3]
Guida verificata passo dopo passo1
Identify the balanced chemical equation: \(\mathrm{N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)}\).
Recall that the equilibrium constant expression \(K\) is written as the ratio of the product concentrations raised to their stoichiometric coefficients over the reactant concentrations raised to their stoichiometric coefficients.
Write the general form of the equilibrium constant expression for this reaction: \(K = \frac{[\mathrm{NH_3}]^{2}}{[\mathrm{N_2}][\mathrm{H_2}]^{3}}\).
Note that the exponents correspond to the coefficients in the balanced equation: 2 for \(\mathrm{NH_3}\), 1 for \(\mathrm{N_2}\), and 3 for \(\mathrm{H_2}\).
Confirm that the equilibrium constant expression matches the form \(K = \frac{[\mathrm{NH_3}]^{2}}{[\mathrm{N_2}][\mathrm{H_2}]^{3}}\) and not any other variation.
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