Scelta multipla
A solution contains 34.2 grams and is 45.5% by mass NaF. How many moles of NaF are present in the solution?
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3. Chemical Reactions
Stoichiometry
Scelta multipla
When 0.100 moles of bromine (Br_2) react with excess hydrogen gas (H_2) according to the equation Br_2 + H_2 → 2 HBr, how many grams of HBr will be produced?
A
3.65 g
B
18.1 g
C
36.2 g
D
8.05 g
Guida verificata passo dopo passo1
Write down the balanced chemical equation: \(\mathrm{Br_2 + H_2 \rightarrow 2\ HBr}\).
Identify the given information: 0.100 moles of \(\mathrm{Br_2}\) and excess \(\mathrm{H_2}\), meaning \(\mathrm{Br_2}\) is the limiting reactant.
Use the mole ratio from the balanced equation to find moles of \(\mathrm{HBr}\) produced. According to the equation, 1 mole of \(\mathrm{Br_2}\) produces 2 moles of \(\mathrm{HBr}\), so multiply 0.100 moles of \(\mathrm{Br_2}\) by 2 to get moles of \(\mathrm{HBr}\).
Calculate the molar mass of \(\mathrm{HBr}\) by adding the atomic masses of hydrogen (approximately 1.01 g/mol) and bromine (approximately 79.90 g/mol).
Multiply the moles of \(\mathrm{HBr}\) by its molar mass to find the mass of \(\mathrm{HBr}\) produced in grams.
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