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Which ions are formed when Sr(CH3COO)2 dissociates in water?
A
Sr^{2+} and 2 CO_3^{2-}
B
Sr^{+} and CH3COO^{-}
C
Sr^{2+} and 2 CH3COO^{-}
D
Sr^{2+} and 2 CH3COOH
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1
Identify the compound given: Sr(CH3COO)2, which is strontium acetate. It consists of one strontium ion and two acetate ions.
Recall that strontium (Sr) is an alkaline earth metal in group 2 of the periodic table, so it typically forms a \(\mathrm{Sr^{2+}}\) ion when it dissociates in water.
Recognize that the acetate ion is the conjugate base of acetic acid (CH3COOH) and carries a single negative charge, so it is written as \(\mathrm{CH_3COO^{-}}\).
When Sr(CH3COO)2 dissolves in water, it dissociates into one \(\mathrm{Sr^{2+}}\) ion and two \(\mathrm{CH_3COO^{-}}\) ions, reflecting the stoichiometry of the compound.
Therefore, the ions formed are \(\mathrm{Sr^{2+}}\) and 2 \(\mathrm{CH_3COO^{-}}\) ions, not carbonate ions or neutral acetic acid molecules.